# 电话号码的字母组合
给定一个仅包含数字 2-9 的字符串,返回所有它能表示的字母组合。答案可以按 任意顺序 返回。
给出数字到字母的映射如下(与电话按键相同)。注意 1 不对应任何字母。
示例
输入:digits = "23"
输出:["ad","ae","af","bd","be","bf","cd","ce","cf"]
class Solution { | |
private static final String[] MAPPING = new String[]{"", "", "abc", "def", "ghi", "jkl", "mno", "pqrs", "tuv", "wxyz"}; | |
private final List<String> ans = new ArrayList<>(); | |
private char[] digits, path; | |
public List<String> letterCombinations(String digits) { | |
int n = digits.length(); | |
if (n == 0) return List.of(); | |
this.digits = digits.toCharArray(); | |
path = new char[n]; | |
dfs(0); | |
return ans; | |
} | |
private void dfs(int i) { | |
if (i == digits.length) { | |
ans.add(new String(path)); | |
return; | |
} | |
for (char c : MAPPING[digits[i] - '0'].toCharArray()) { | |
path[i] = c; | |
dfs(i + 1); | |
} | |
} | |
} |